2c^2-1200c=-525

Solution for 2c^2-1200c=-525 equation:

2c^2-1200c=-525

We move all terms to the left:

2c^2-1200c-(-525)=0

We add all the numbers together, and all the variables

2c^2-1200c+525=0

a = 2; b = -1200; c = +525;
Δ = b2-4ac
Δ = -12002-4·2·525
Δ = 1435800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1435800}=\sqrt{100*14358}=\sqrt{100}*\sqrt{14358}=10\sqrt{14358}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1200)-10\sqrt{14358}}{2*2}=\frac{1200-10\sqrt{14358}}{4}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1200)+10\sqrt{14358}}{2*2}=\frac{1200+10\sqrt{14358}}{4}
$